int (*myFunc)(double b, int c);

int (*p)(int a, int b);//p是一個指向函數(shù)的指針變量，所指函數(shù)的返回值類型為整型
int *p(int a, int b);//p是函數(shù)名，此函數(shù)的返回值類型為整型指針

int fn1(int x, int y); int fn2(int x);

int (*p1)(int a, int b); int (*p2)(int a);

p1 = fn1; //正確
p2 = fn2; //正確
p1 = fn2; //產(chǎn)生編譯錯誤

#include <iostream>
using namespace std;

class test
{
public:
  test()
  {
    cout<<"constructor"<<endl;
  }
  int fun1(int a, char c)
  {
    cout<<"this is fun1 call:"<<a<<" "<<c<<endl;
    return a;
  }
  void fun2(double d)const
  {
    cout<<"this is fun2 call:"<<d<<endl;
  }
  static double fun3(char buf[])
  {
    cout<<"this is fun3 call:"<<buf<<endl;
    return 3.14;
  }
};

int main()
{
  // 類的靜態(tài)成員函數(shù)指針和c的指針的用法相同
  double (*pstatic)(char buf[]) = NULL;//不需要加類名
  pstatic = test::fun3; //可以不加取地址符號
  pstatic("myclaa");
  pstatic = &test::fun3;
  (*pstatic)("xyz");

  //普通成員函數(shù)
  int (test::*pfun)(int, char) = NULL; //一定要加類名
  pfun = &test::fun1; //一定要加取地址符號
  test mytest;
  (mytest.*pfun)(1, 'a'); //調(diào)用是一定要加類的對象名和*符號

  //const 函數(shù)（基本普通成員函數(shù)相同）
  void (test::*pconst)(double)const = NULL; //一定要加const
  pconst = &test::fun2;
  test mytest2;
  (mytest2.*pconst)(3.33);

//  //構(gòu)造函數(shù)或者析構(gòu)函數(shù)的指針，貌似不可以，不知道c++標(biāo)準(zhǔn)有沒有規(guī)定不能有指向這兩者的函數(shù)指針
//  (test::*pcon)() = NULL;
//  pcon = &test.test;
//  test mytest3;
//  (mytest3.*pcon)();

  return 0;
}