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C經(jīng)典算法之二分查找法

來(lái)源:本站原創(chuàng)|時(shí)間:2020-01-10|欄目:C語(yǔ)言|點(diǎn)擊: 次

C經(jīng)典算法之二分查找法

1.根據(jù)key查找所在數(shù)組的位置

#include <stdio.h>
/*
 key = 9;
 1 2 3 4 5 6 7 8
 arr 3, 4, 5, 7, 9 , 11, 21, 23
 low = 1  mid = (low + high)/2 = 4      high = 8;
 one   arr[mid] = 7 < 9;  so low = mid + 1 = 5; high = 8; mid = (low + high)/2 = 6
 two   arr[mid] = 11 > 9  so low = 5 ,   high = mid - 1 = 5 mid = 5;
 arr[mid] = 9 == key

 if(key = 10) low = mid + 1 > high

 */
int main(int argc, const char * argv[])
{
 int findByHalf(int arr[], int len, int key);

 int arr[] = {3, 4 , 5, 7, 9 , 11, 21, 23};
 int len = sizeof(arr)/sizeof(int);

 int index = findByHalf(arr, len, 88);

 printf("index = %d\n", index);
 return 0;
}

int findByHalf(int arr[], int len, int key){
 int low = 0;
 int high = len - 1;

 int mid ;


 while(low <= high){
  mid = (low + high) / 2;
  //右邊查找
  if (key > arr[mid]) {
   low = mid + 1;
  //左邊查找
  }else if (key > arr[mid]) {
   high = mid - 1;
  }else{
   return mid;
  }

 }
 return -1;
}

2.插入一個(gè)數(shù),得到其所在數(shù)組的位置

#include <stdio.h>
/*
 key = 9;
 1 2 3 4 5 6 7 8
 arr 3, 4, 5, 7, 9 , 11, 21, 23
 low = 1  mid = (low + high)/2 = 4      high = 8;
 one   arr[mid] = 7 < 9;  so low = mid + 1 = 5; high = 8; mid = (low + high)/2 = 6
 two   arr[mid] = 11 > 9  so low = 5 ,   high = mid - 1 = 5 mid = 5;
 arr[mid] = 9 == key

 if(key = 10) low = mid + 1 > high

 */
int main(int argc, const char * argv[])
{
 int findByHalf(int arr[], int len, int key);

 int arr[] = {3, 4 , 5, 7, 9 , 11, 21, 23};
 int len = sizeof(arr)/sizeof(int);

 int index = findByHalf(arr, len, 88);

 printf("index = %d\n", index);
 return 0;
}

int insertByHalf(int arr[], int len, int key){
 int low = 0;
 int high = len - 1;

 int mid ;


 while(low <= high){
  mid = (low + high) / 2;
  //右邊查找
  if (key > arr[mid]) {
   low = mid + 1;
  //左邊查找
  }else if (key > arr[mid]) {
   high = mid - 1;
  }else{
   //如果arr[mid] == key
   //就把key插入到這個(gè)數(shù)的后面
   return mid + 1;
  }

 }
 //如果low > high 說(shuō)明 key > arr[mid];
 //就把key插入到low對(duì)應(yīng)的 這個(gè)數(shù)的位置
 return low;
}

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