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C語言實現(xiàn)停車場管理系統(tǒng)

來源:本站原創(chuàng)|時間:2020-01-10|欄目:C語言|點擊: 次

問題描述:停車場是一個能放n輛車的狹長通道,只有一個大門,汽車按到達的先后次序停放。若車場滿了,車要停在門外的便道上等候,一旦有車走,則便道上第一輛車進入。當停車場中的車離開時,由于通道窄,在它后面呢的車要先退出,待它走后再依次進入。汽車離開時按停放時間收費。

基本功能要求:

(1)建立三個數(shù)據(jù)結構分別是:停放隊列、讓路棧、等候隊列。
(2)輸入數(shù)據(jù)模擬管理過程,數(shù)據(jù)(入或出,車號)。

停車管理系統(tǒng)是C語言中隊列和棧比較簡單的應用,需要注意的是停車隊列、等候隊列、讓路棧結構體的構建。在寫代碼時,出隊列入棧和出棧入隊列時,指針容易出錯而造成段錯誤,應當注意。我所寫的代碼如下:

//定義結構體

#include <stdio.h>
#include <stdlib.h>

#define F 0
#define T 1
#define MAX 3

typedef struct Node  //數(shù)據(jù)
{
  int number;
  int time;
}Node;

typedef struct QueueNode  //隊列結點
{
  struct Node infom;
  struct QueueNode * next;
}*QueueNode;

typedef struct LinkQueue  //鏈隊列
{
  struct QueueNode * front;
  struct QueueNode * rear;
}LinkQueue;

typedef struct stack     //棧結點
{
  struct Node data;
  struct stack *next;
}*StackNode;

typedef struct LinkStack   //鏈棧
{
  StackNode top;
  int count;
}LinkStack;

//函數(shù)實現(xiàn)

void menu(LinkQueue *wait,LinkQueue *park,LinkStack *giveway,int num,int t);//菜單
int init(LinkQueue *wait,LinkQueue *park,LinkStack *giveway);//初始化
int linklength(LinkQueue q);//查看長度
int enqueue(LinkQueue *q,int num,int t);//入隊列
int dequeue(LinkQueue *q,int *num,int *t);//出隊列
void park1(LinkQueue *wait,LinkQueue *park);//停車函數(shù)
int push(LinkStack *s,int num,int t);//入棧
int pop(LinkStack *s,int *num,int *t);//出棧
void leave2(LinkQueue *wait,LinkQueue *park,LinkStack *giveway,int num,int t);//離開函數(shù)
void view3(LinkQueue wait,LinkQueue park);//查看停車場狀態(tài)

int main()
{
  LinkQueue wait;
  LinkQueue park;
  LinkStack giveway;
  int num = 0;
  int t = 0;
  init(&wait,&park,&giveway);
  menu(&wait,&park,&giveway,num,t);
  return 0;
}

int init(LinkQueue *wait,LinkQueue *park,LinkStack *giveway)
{
  QueueNode newnode1 = (QueueNode)malloc(sizeof(struct QueueNode));
  if(NULL == newnode1)
  {
    return F;
  }
  newnode1->next = NULL;
  wait->front = newnode1;
  wait->rear = newnode1;

  QueueNode newnode2 = (QueueNode)malloc(sizeof(struct QueueNode));
  if(NULL == newnode2)
  {
    return F;
  }
  newnode2->next = NULL;
  park->front = newnode2;
  park->rear = newnode2;

  giveway->top = NULL;
  giveway->count = 0;
}

void menu(LinkQueue *wait,LinkQueue *park,LinkStack *giveway,int num,int t)
{
  printf("**********Welcome to our Car Parking !**********\n");
  printf("********** Please choose function  **********\n");
  printf("**********     1 : park.     **********\n");
  printf("**********     2 : leave.     **********\n");
  printf("**********     3 : view.     **********\n");
  printf("**********     4 : exit.     **********\n");
  int option;
  scanf("%d",&option);
  switch(option)
  {
    case 1:{
      park1(wait,park);
      printf("停車完成!\n");
      menu(wait,park,giveway,num,t);
      break;
    }
    case 2:{
      leave2(wait,park,giveway,num,t);
      menu(wait,park,giveway,num,t);
      break;
    }
    case 3:{
      view3(*wait,*park);
      menu(wait,park,giveway,num,t);
      break;
    }
    case 4:{
      printf("**********   歡迎再次使用,謝謝!  **********\n");
      break;
    }
    default:{
      printf("**********   請輸入正確的指令!  **********\n");
      menu(wait,park,giveway,num,t);
      break;
    }
  }

}

int linklength(LinkQueue q)
{
  int i = 0;
  while(q.front != q.rear)
  {
    i++;
    q.front = q.front->next;
  }
  return i;
}

int enqueue(LinkQueue *q,int num,int t)
{
  QueueNode newnode = (QueueNode)malloc(sizeof(struct QueueNode));
  if(NULL == newnode)
  {
    return F;
  }
  newnode->infom.number = num;
  newnode->infom.time = t;
  newnode->next = NULL;
  q->rear->next = newnode;
  q->rear = newnode;
  return T;
}

int dequeue(LinkQueue *q,int *num,int *t)
{
  if(q->front == q->rear)
  {
    printf("the queue is empty!\n");
    return F;
  }
  *num = q->front->next->infom.number;
  *t = q->front->next->infom.time;
  QueueNode temp = q->front->next;
  q->front->next = temp->next;
  if(temp->next == NULL)
  {
    q->rear = q->front;
  }
  free(temp);
  return T;
}

void park1(LinkQueue *wait,LinkQueue *park)
{
  printf("請輸入車號和停車時間\n");
  int num,t;
  scanf("%d,%d",&num,&t);
  if(linklength(*park) >= MAX)
  {
    printf("停車場已滿,進入等待區(qū)!\n");
    enqueue(wait,num,t);
  }
  else
  {
    enqueue(park,num,t);
  }
}

int push(LinkStack *s,int num,int t)
{
  StackNode newnode = (StackNode)malloc(sizeof(struct stack));
  if(NULL == newnode)
  {
    return F;
  }
  newnode->data.number = num;
  newnode->data.time = t;
  newnode->next = s->top;
  s->top = newnode;
  s->count++;
  return T;
}

int pop(LinkStack *s,int *num,int *t)
{
  if(0 == s->count)
  {
    printf("the stack is empty !\n");
    return F;
  }
  *num = s->top->data.number;
  *t = s->top->data.time;
  StackNode temp = s->top;
  s->top = s->top->next;
  free(temp);
  s->count--;
  return T;
}

void leave2(LinkQueue *wait,LinkQueue *park,LinkStack *giveway,int num,int t)
{
  printf("請輸入要離開車的車號\n");
  int leavenumber;
  scanf("%d",&leavenumber);
  int i = 0;
  QueueNode head = park->front;
  while(head != park->rear)
  {
    if(head->next->infom.number != leavenumber)
    {
      head = head->next;
      i++;
    }
    else
      break;
  }
  int j = 0;
  if(i <= MAX-1)
  {
    while(j != i)
    {
      dequeue(park,&num,&t);
      push(giveway,num,t);
      j++;
    }
    dequeue(park,&num,&t);
  }
  else
  {
    printf("查無此車!\n");
  }
  while(giveway->top != NULL)
  {
    pop(giveway,&num,&t);
    enqueue(park,num,t);
  }
  if(linklength(*wait) != 0)
  {
    dequeue(wait,&num,&t);
    enqueue(park,num,t);
  }
}

void view3(LinkQueue wait,LinkQueue park)
{
  printf("********************  目前停車場狀況  ********************\n");
  printf("停車場共%d個車位,當前停車場共有%d量車,等待區(qū)共有%d量車\n",
    MAX,linklength(park),linklength(wait));
  printf("**************************************************************\n");
  printf("車  號:");
  QueueNode head1 = park.front;
  QueueNode head2 = park.front;
  while(head1 != park.rear)
  {
    printf("%d ",head1->next->infom.number);
    head1 = head1->next;
  }
  printf("\n");
  printf("停車時間:");
  while(head2 != park.rear)
  {
    printf("%d ",head2->next->infom.time);
    head2 = head2->next;
  }
  printf("\n");
}

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