Create proc sp_Insert_Student
   @No char(10),
   @Name varchar(20),
   @Sex char(2),
   @Age int,
   @rtn int output
 as
 declare
   @tmpName varchar(20),
  @tmpSex char(2),
  @tmpAge int
  
  if exists(select * from Student where No=@No)
    begin
      select @tmpName=Name,@tmpSex=Sex,@tmpAge=Age from Student where No=@No
      if ((@tmpName=@Name) and (@tmpSex=@Sex) and (@tmpAge=@Age))
        begin
          set @rtn=0  --有相同的數(shù)據(jù)，直接返回值
        end
      else
        begin
          update Student set Name=@Name,Sex=@Sex,Age=@Age where No=@No
          set @rtn=2  --有主鍵相同的數(shù)據(jù)，進(jìn)行更新處理
        end
    end
  else
    begin
      insert into Student values(@No,@Name,@Sex,@Age)
      set @rtn=1  --沒(méi)有相同的數(shù)據(jù)，進(jìn)行插入處理
    end

 declare @rtn int
 exec sp_Insert_Student '1101','張三','男',23,@rtn output
 
 if @rtn=0
   print '已經(jīng)存在相同的。'
 else if @rtn=1
   print '插入成功。'
 else
   print '更新成功'